document.write( "Question 370732: using long division divide x^3+4^2-3x by x^2+4 \n" ); document.write( "
Algebra.Com's Answer #264531 by jsmallt9(3758)\"\" \"About 
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\r\n" );
document.write( "        x   + 4\r\n" );
document.write( "       ____________________________________\r\n" );
document.write( "x^2+4 / x^3 + 4x^2 - 3x\r\n" );
document.write( "        x^3        + 4x   <== Note how like terms are lined up!\r\n" );
document.write( "       ------------\r\n" );
document.write( "              4x^2 - 7x\r\n" );
document.write( "              4x^2       + 16\r\n" );
document.write( "              ---------------\r\n" );
document.write( "                   - 7x  - 16\r\n" );
document.write( "

\n" ); document.write( "Since x^2 will not divide into -7x, we are done. The -7x-16 represents the remainder. And with the remainder we make a fraction out of it and the divisor. So:
\n" ); document.write( "\"%28x%5E3+%2B+4x%5E2+-3x%29%2F%28x%5E2%2B4%29+=+x+%2B+4+%2B+%28-7x-16%29%2F%28x%5E2%2B4%29\" \n" ); document.write( "
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