document.write( "Question 371335: A train left a railroad station in N.Y. at 9:00 AM bound for Washington, D.C. traveling at a uniform speed. At 10:30 AM another train left the same station bound for Washington D.C. (on a different track) averaging 20 mph more than the first train and passed the first train 180 miles from N.Y. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #264528 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A train left a railroad station in N.Y. at 9:00 AM bound for Washington, D.C. traveling at a uniform speed. At 10:30 AM another train left the same station bound for Washington D.C. (on a different track) averaging 20 mph more than the first train and passed the first train 180 miles from N.Y. Find the speed of each train. \n" ); document.write( "----- \n" ); document.write( "1st train DATA: \n" ); document.write( "distance = 180 mi ; time = x hrs ; rate = 180/x mph \n" ); document.write( "--- \n" ); document.write( "2nd train DATA: \n" ); document.write( "distance = 180 mi ; time = (x-(3/2)) hrs ; rate = 180/(x-(3/2)) mph \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "2nd train rate - 1st train rate = 20 mph \n" ); document.write( "180/(x-(3/2)) - 180/x = 20 \n" ); document.write( "----- \n" ); document.write( "2/(2x-3) - 1/x = 1/9 \n" ); document.write( "----- \n" ); document.write( "Multiply thru by 9x(2x-3) to get: \n" ); document.write( "18x - 9(2x-3) = x(2x-3) \n" ); document.write( "27 = 2x^2-3x \n" ); document.write( "2x^2 - 3x - 27 = 0 \n" ); document.write( "--- \n" ); document.write( "x = 4.5 hrs \n" ); document.write( "--- \n" ); document.write( "1st train rate = 180/4.5 = 40 mph \n" ); document.write( "--- \n" ); document.write( "2nd train rate = 180/(4.5-1.5) = 180/3 = 60 mph \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |