document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=371293>Question 371293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you show the correct way to work this system of linear equations word problem out?  Thanks! \r<BR>\n" );
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document.write( "Problem:  Water and bleach are to be mixed in a ration of 50 to 1. How many milliliters of each are needed to make 800ml of the mix?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264511 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Problem: Water and bleach are to be mixed in a ration of 50 to 1. How many milliliters of each are needed to make 800ml of the mix? <BR>\n" );
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document.write( "50 to 1 is the same as 50x to x where 50x is water and x is bleach.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "water + bleach = 800ml<BR>\n" );
document.write( "50x + x = 800<BR>\n" );
document.write( "51x = 800<BR>\n" );
document.write( "x = 800/51<BR>\n" );
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document.write( "Water = 50(800/51) = 784 ml (amt. of water<BR>\n" );
document.write( "Bleach = 800/51 = 15.69 ml (amt. of bleach)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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