document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=371260>Question 371260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the primeter of a rectangle is 36 cm and its area is 80 sq.cm. find its duimensions<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264492 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264492\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter = 36<BR>\n" );
document.write( "2*(L+W)=36<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "L+W=18<BR>\n" );
document.write( "..<BR>\n" );
document.write( "ARea =L*W<BR>\n" );
document.write( "L*W = 80<BR>\n" );
document.write( "L= 80/W<BR>\n" );
document.write( "plug value of L in first equation<BR>\n" );
document.write( "80/W + W = 36<BR>\n" );
document.write( "(80+W^2)/W=36<BR>\n" );
document.write( "80+W^2 = 36W<BR>\n" );
document.write( "w^2-36W+80=0<BR>\n" );
document.write( "use the quadratic formula to find the roots<BR>\n" );
document.write( "x1= ((36+sqrt(976))/2<BR>\n" );
document.write( "X1=33.6<BR>\n" );
document.write( "..<BR>\n" );
document.write( "X2=((36-sqrt(976))/2<BR>\n" );
document.write( "X2=2.38<BR>\n" );
document.write( "Dimensions are 33.6 by 2.4 cm<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
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