document.write( "Question 371212: One number is 3 less than a second number. Twice the second number is 9 less than 5 times the first. \n" ); document.write( "

Algebra.Com's Answer #264479 by mananth(16946) $\"\"$ $\"About$

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let x & y be the two numbers
\n" ); document.write( "x= y-3
\n" ); document.write( "x-y =-3....................1
\n" ); document.write( "2y= 5x-9
\n" ); document.write( "2y-5x=-9...................2
\n" ); document.write( "multiply equation 1 by 2
\n" ); document.write( "2x-2y=-6
\n" ); document.write( "add it to (2)
\n" ); document.write( "-3x=-15
\n" ); document.write( "/-3
\n" ); document.write( "x=5
\n" ); document.write( "..
\n" ); document.write( "plug value of x in equation 1
\n" ); document.write( "5-y=-3
\n" ); document.write( "-y=-5-3
\n" ); document.write( "-y=-8
\n" ); document.write( "y=8
\n" ); document.write( "...
\n" ); document.write( "the numbers are 5 & 8
\n" ); document.write( " \n" ); document.write( "

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