document.write( "Question 371180: one leg of a triangle is 1 centimeter shorter than the other leg and the hypotenuse is 2 centimeters longer than the longer leg. What are the lengths of the sides of the triangle? \n" ); document.write( "
Algebra.Com's Answer #264472 by mananth(16946)\"\" \"About 
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let one leg be x
\n" ); document.write( "other leg = x-1
\n" ); document.write( "hypotenuse = x+2
\n" ); document.write( "..
\n" ); document.write( "x^2+(x-1)^2=(x+2)^2
\n" ); document.write( "x^2+x^2-2x+1= x^2 +4x+4
\n" ); document.write( "x^2-6x-3=0
\n" ); document.write( "solve for x using quadratic formula
\n" ); document.write( "discriminant = 48
\n" ); document.write( "x1=((6+sqrt(48))/2
\n" ); document.write( "x1= 6.46cm one leg
\n" ); document.write( "other leg will be 5.46cm
\n" ); document.write( "hypotenuse = 7.46cm
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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