document.write( "Question 371202: A rectangular field with area 4500 square meters is enclosed with 300 meters of fencing. Find its dimensions. (HINT: set up a system) \n" ); document.write( "
Algebra.Com's Answer #264470 by mananth(16946)\"\" \"About 
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let length be l
\n" ); document.write( "width w
\n" ); document.write( "..
\n" ); document.write( "Area = l*w
\n" ); document.write( "l*w= 4500
\n" ); document.write( "l= 4500/w
\n" ); document.write( "...
\n" ); document.write( "perimeter = 2(l+w)
\n" ); document.write( "2(l+w)=300
\n" ); document.write( "/2
\n" ); document.write( "l+w = 150
\n" ); document.write( "..
\n" ); document.write( "plug value of l
\n" ); document.write( "4500/w +w = 150
\n" ); document.write( "(4500+w^2)/w=150
\n" ); document.write( "4500+w^2=150w
\n" ); document.write( "w^2-150+4500=0
\n" ); document.write( "discriminant = 4500
\n" ); document.write( "solve for x using quadratic equation\r
\n" ); document.write( "\n" ); document.write( "x1=(150+sqrt(4500))/2
\n" ); document.write( "x1=108.5 m
\n" ); document.write( "x2= 150-sqrt(4500))/2
\n" ); document.write( "x2= 41.5
\n" ); document.write( "The dimensions are 108.5m by 41.5 m\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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