document.write( "Question 41041: The length of a sign is 4 inches more than the width. The area is 45 square inches. Identify the length and the width of the sign.
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Algebra.Com's Answer #26447 by checkley71(8403) ![]() You can put this solution on YOUR website! (4+X)*X=45 OR 4X+X~2-45=0 OR (X-5)(X+9)=0 OR X=5 & X=-9\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |