document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=371209>Question 371209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a triangular garden has an area or 45 square meters. its base is 3 meters longer than twice its height. how long is the base?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264465 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let height of triangle be x<BR>\n" );
document.write( "base = 2x+3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area of triangle = 1/2 * base * height<BR>\n" );
document.write( "1/2 * x*(2x+3) = 45<BR>\n" );
document.write( "..<BR>\n" );
document.write( "*2       *2<BR>\n" );
document.write( "x(2x+3) = 90<BR>\n" );
document.write( "2x^2+3x=90<BR>\n" );
document.write( "2x^2+3x-90=0<BR>\n" );
document.write( "2x^2+15x-12x-90=0<BR>\n" );
document.write( "x(2x+15)-6(2x+15)=0<BR>\n" );
document.write( "(2x+15)(x-6)=0<BR>\n" );
document.write( "x = 6 m the height<BR>\n" );
document.write( "base = 2x+3 = 2*6 +3 = 15m<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );