document.write( "Question 41041: The length of a sign is 4 inches more than the width. The area is 45 square inches. Identify the length and the width of the sign.
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Algebra.Com's Answer #26443 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
I am going to guess that this sign is rectangular.
\n" ); document.write( "Length(l) = w + 4
\n" ); document.write( "Width(w) = w
\n" ); document.write( "Length * Width = Area
\n" ); document.write( "(w + 4)(w) = 45
\n" ); document.write( "w^2 + 4w = 45
\n" ); document.write( "w^2 + 4w - 45 = 0
\n" ); document.write( "(w + 9)(w - 5) = 0
\n" ); document.write( " $\"w+=+-9\"$ or $\"w+=+5\"$
\n" ); document.write( "Since the width can not be negative, your width is: $\"w+=+5\"$
\n" ); document.write( "Plug:
\n" ); document.write( "Length = w + 4
\n" ); document.write( "Length = 5 + 4
\n" ); document.write( "Length = 9 \n" ); document.write( "

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