document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41034>Question 41034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Chemist has one solution that is 60% chlorinated and another that is 40% chlorinated. How much of the first (60%) solution is needed to make a 100L solution that is 50% chlorinated? <BR>\n" );
document.write( "--so i put it like this right?<BR>\n" );
document.write( "--x(.60) + (100-x)(.50) = 100(.50)<BR>\n" );
document.write( ".6x + 50 - .5x = 50<BR>\n" );
document.write( ".1x = 100<BR>\n" );
document.write( "x = 1000<BR>\n" );
document.write( "100-x = -100<BR>\n" );
document.write( "Is this right???\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26442 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .60X+(100-X).4=100*.5 OR .6X+40-.4X=50 OR .2X+40=50 OR .2X=10 OR X=10/.2 OR\r<BR>\n" );
document.write( "\n" );
document.write( "X=50L OF 60% & 50L OF 40% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );