document.write( "Question 371154: 2x + 6y = 50
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document.write( "10x + 0y = 10
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document.write( "Solve by the substitution method. \n" );
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Algebra.Com's Answer #264419 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2x + 6y = 50 \n" ); document.write( "10x + 0y = 10 \n" ); document.write( "10x+0=10 \n" ); document.write( "10x=10 \n" ); document.write( "/10 \n" ); document.write( "x= 1 \n" ); document.write( "... \n" ); document.write( "plug value of x in first equation \n" ); document.write( "2x+6y= 50 \n" ); document.write( "2*1+6y=50 \n" ); document.write( "2+6y=50 \n" ); document.write( "-2 -2 \n" ); document.write( "6y=50-2 \n" ); document.write( "6y=48 \n" ); document.write( "/6 \n" ); document.write( "6y/6 = 48/6\r \n" ); document.write( "\n" ); document.write( "y =8\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |