document.write( "Question 371154: 2x + 6y = 50
\n" ); document.write( "10x + 0y = 10
\n" ); document.write( "Solve by the substitution method.
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Algebra.Com's Answer #264419 by mananth(16946)\"\" \"About 
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2x + 6y = 50
\n" ); document.write( "10x + 0y = 10
\n" ); document.write( "10x+0=10
\n" ); document.write( "10x=10
\n" ); document.write( "/10
\n" ); document.write( "x= 1
\n" ); document.write( "...
\n" ); document.write( "plug value of x in first equation
\n" ); document.write( "2x+6y= 50
\n" ); document.write( "2*1+6y=50
\n" ); document.write( "2+6y=50
\n" ); document.write( "-2 -2
\n" ); document.write( "6y=50-2
\n" ); document.write( "6y=48
\n" ); document.write( "/6
\n" ); document.write( "6y/6 = 48/6\r
\n" ); document.write( "\n" ); document.write( "y =8\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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