document.write( "Question 371108: There are ten raffle tickets, two of which are winners. Find the probability that in a sample of 6 tickets there will be no more than one winning ticket. I am more concerned with how to find the answer then I am with what the actual answer is. Can you please explain. Thanks.
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Algebra.Com's Answer #264405 by jvan(28)\"\" \"About 
You can put this solution on YOUR website!
Hi! =] I'm glad you are interested in learning how to solve, rather than just what the answer is.\r
\n" ); document.write( "\n" ); document.write( "Since there are 2 winning tickets out of 10, you have a probability of 2/10 (simplified to 1/5) winning tickets. Then the probability of getting losing tickets is 1 - 1/5 = 4/5. Notice that the probability always add up to 1 for some event (i.e. winning+losing tickets = 1= 100% of all tickets). We first have to find the chance of one of the 6 tickets being a winning ticket. Multiply the probabilities together, a total of 5 losing and 1 winning ticket gives: \"4%2F5%2A4%2F5%2A4%2F5%2A4%2F5%2A4%2F5%2A1%2F5+=+0.0655\" chance of there being 1 winning ticket out of the 6 total tickets. Next we find the chance of there being no winning tickets in the 6 total tickets: \"4%2F5%2A4%2F5%2A4%2F5%2A4%2F5%2A4%2F5%2A4%2F5+=+0.262\". Then the chance of there being NO MORE THAN ONE winning ticket in the 6 total tickets is : 0.0655+0.262 = 0.328, which is equal to 32.8%. \r
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