document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=371099>Question 371099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i find the answer for 2x^2-11x+12=0 i get stuck i know that you have to factor 12 to get -11 which be -12, 1 but from there i dont know what to do  can you please help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264390 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264390\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2-11x+12=0<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2*12 = 24<BR>\n" );
document.write( "a+b = -11<BR>\n" );
document.write( "ab=24<BR>\n" );
document.write( "-8,-3<BR>\n" );
document.write( "...<BR>\n" );
document.write( "2x^2-8x-3+12<BR>\n" );
document.write( "2x(x-4)-3(x-4)=0<BR>\n" );
document.write( "(x-4)(2x-3)=0<BR>\n" );
document.write( "x= 4 OR x 3/2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );