document.write( "Question 371089: The sum of three numbers is 44. The second number is is three times the first number and the third number is 6 less than the first number. Find the three numbers. How do I write this in equations. \n" ); document.write( "
Algebra.Com's Answer #264386 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let first number be x \n" ); document.write( "second number is 3 times = 3x \n" ); document.write( "third number =x-6 \n" ); document.write( ".. \n" ); document.write( "add them up \n" ); document.write( ".. \n" ); document.write( "x+3x+x-6 = 44 \n" ); document.write( "5x-6 =44 \n" ); document.write( "+6 +6 \n" ); document.write( "5x= 50 \n" ); document.write( "/5 \n" ); document.write( "x= 50/5 \n" ); document.write( "x= 10 first number \n" ); document.write( "3x is the second number = 3*10=30 \n" ); document.write( "x-6 is the third number = 3=10-6=4 \n" ); document.write( ".. \n" ); document.write( "10, 30, 4 \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca+\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |