document.write( "Question 371089: The sum of three numbers is 44. The second number is is three times the first number and the third number is 6 less than the first number. Find the three numbers. How do I write this in equations. \n" ); document.write( "
Algebra.Com's Answer #264386 by mananth(16946)\"\" \"About 
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let first number be x
\n" ); document.write( "second number is 3 times = 3x
\n" ); document.write( "third number =x-6
\n" ); document.write( "..
\n" ); document.write( "add them up
\n" ); document.write( "..
\n" ); document.write( "x+3x+x-6 = 44
\n" ); document.write( "5x-6 =44
\n" ); document.write( "+6 +6
\n" ); document.write( "5x= 50
\n" ); document.write( "/5
\n" ); document.write( "x= 50/5
\n" ); document.write( "x= 10 first number
\n" ); document.write( "3x is the second number = 3*10=30
\n" ); document.write( "x-6 is the third number = 3=10-6=4
\n" ); document.write( "..
\n" ); document.write( "10, 30, 4
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca+\r
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