document.write( "Question 41032: The Perimeter of a rectangle shaped lawn is 52 feet and the area is 144 square feet. What are the dimensions of the lawn?
\n" ); document.write( "isn’t it 12x12x12x12?
\n" ); document.write( "Thank you
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #26438 by Nate(3500) $\"\"$ $\"About$

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Area: lw
\n" ); document.write( "lw = 144
\n" ); document.write( "l = 144/w
\n" ); document.write( "Perimeter: 2l + 2w
\n" ); document.write( "2l + 2w = 52
\n" ); document.write( "Combine:
\n" ); document.write( "2l + 2w = 52
\n" ); document.write( "2(144/w) + 2w = 52
\n" ); document.write( "288/w + 2w = 52
\n" ); document.write( "288 + 2w^2 = 52w
\n" ); document.write( "2w^2 - 52w + 288 = 0
\n" ); document.write( "w^2 - 26w + 144 = 0
\n" ); document.write( "(w - 18)(w - 8) = 0
\n" ); document.write( " $\"w+=+18\"$ or $\"w+=+8\"$
\n" ); document.write( "Plug:
\n" ); document.write( "lw = 144
\n" ); document.write( "l18 = 144
\n" ); document.write( "l = 8
\n" ); document.write( "or Plug:
\n" ); document.write( "lw = 144
\n" ); document.write( "l8 = 144
\n" ); document.write( "l = 18
\n" ); document.write( "Since the length is longer, you would have: length = $\"18\"$ and width = $\"8\"$ \n" ); document.write( "

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