document.write( "Question 41028: When the reciprocal of 3 times a number is subtracted from the reciprocal of the #, the result is one-sixth. find the number.
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Algebra.Com's Answer #26436 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Try this:\r
\n" ); document.write( "\n" ); document.write( " $\"1%2Fn+-+1%2F3n+=+1%2F6\"$ Simplify.
\n" ); document.write( " $\"%283-1%29%2F3n+=+1%2F6\"$
\n" ); document.write( " $\"2%2F3n+=+1%2F6\"$ Multiply both sides by 3n.
\n" ); document.write( " $\"2+=+3n%2F6\"$ Multiply both sides by 6.
\n" ); document.write( " $\"12+=+3n\"$ Finally, divide both sides by 3.
\n" ); document.write( " $\"n+=+4\"$ \r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( " $\"1%2F4+-+1%2F%283%2A4%29+=+1%2F6\"$
\n" ); document.write( " $\"1%2F4+-+1%2F12+=+1%2F6\"$
\n" ); document.write( " $\"3%2F12+-+1%2F12+=+1%2F6\"$
\n" ); document.write( " $\"2%2F12+=+1%2F6\"$
\n" ); document.write( " $\"1%2F6+=+1%2F6\"$ \n" ); document.write( "

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