document.write( "Question 371019: Solve the problem. On a recent trip, Sarah's car traveled 20 mph faster on the first 140 miles than it did on the remaining 80 miles. The total time for the trip was 4 hours. Find the speed of Sarah's car on the first part of the trip. \n" ); document.write( "
Algebra.Com's Answer #264350 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let speed on second leg be x mph \n" ); document.write( "speed on first leg = x+20 \n" ); document.write( ".. \n" ); document.write( "second leg distance = 80 miles \n" ); document.write( "first leg distance = 140 miles \n" ); document.write( ".. \n" ); document.write( "time first leg + time second leg = 4 hours \n" ); document.write( "... \n" ); document.write( "t= d/t \n" ); document.write( "80/x + 140/(x+20)=4 \n" ); document.write( "(80(x+20)+140x)/x(x+20)=4 \n" ); document.write( "80x+1600+140x=4x(x+20) \n" ); document.write( "220x +1600 = 4x^2+80x \n" ); document.write( "4x^2+80x-220x-1600=0 \n" ); document.write( "4x^2-140x-1600=0 \n" ); document.write( "/4 \n" ); document.write( "x^2-35x-400=0 \n" ); document.write( "solve for x using quadratic formula \n" ); document.write( "discriminant = 2825 \n" ); document.write( "x1= (35+sqrt(2825))/2 \n" ); document.write( "x2 will be negative so to be ignored \n" ); document.write( "= 44.07 mph on the second leg. \n" ); document.write( "first leg speed = x+20 = 64.07 mph\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |