document.write( "Question 371019: Solve the problem. On a recent trip, Sarah's car traveled 20 mph faster on the first 140 miles than it did on the remaining 80 miles. The total time for the trip was 4 hours. Find the speed of Sarah's car on the first part of the trip. \n" ); document.write( "
Algebra.Com's Answer #264350 by mananth(16946)\"\" \"About 
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let speed on second leg be x mph
\n" ); document.write( "speed on first leg = x+20
\n" ); document.write( "..
\n" ); document.write( "second leg distance = 80 miles
\n" ); document.write( "first leg distance = 140 miles
\n" ); document.write( "..
\n" ); document.write( "time first leg + time second leg = 4 hours
\n" ); document.write( "...
\n" ); document.write( "t= d/t
\n" ); document.write( "80/x + 140/(x+20)=4
\n" ); document.write( "(80(x+20)+140x)/x(x+20)=4
\n" ); document.write( "80x+1600+140x=4x(x+20)
\n" ); document.write( "220x +1600 = 4x^2+80x
\n" ); document.write( "4x^2+80x-220x-1600=0
\n" ); document.write( "4x^2-140x-1600=0
\n" ); document.write( "/4
\n" ); document.write( "x^2-35x-400=0
\n" ); document.write( "solve for x using quadratic formula
\n" ); document.write( "discriminant = 2825
\n" ); document.write( "x1= (35+sqrt(2825))/2
\n" ); document.write( "x2 will be negative so to be ignored
\n" ); document.write( "= 44.07 mph on the second leg.
\n" ); document.write( "first leg speed = x+20 = 64.07 mph\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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