document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370948>Question 370948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve (y2 + 10y + 21)/(y + 7) ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264343 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To simplify, factor out the numerator:  y2 + 10y + 21 = (y+3)(y+7).  The common factor y + 7 will cancel with the y+7 at the denominator, so in least terms the expression is equal to y+3. </SPAN>\n" );
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