document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=371022>Question 371022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne and Nancy use a metal alloy that is 15% copper to make jewelry.  How many ounces of 10% alloy must be mixed with a 21% alloy to form 121 ounces of the desired alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264342 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = #oz. of 10% alloy,<BR>\n" );
document.write( "121-x =  #oz. of 21% alloy.  Then <BR>\n" );
document.write( "0.10x + 0.21(121 - x) = 0.15*121,<BR>\n" );
document.write( "0.10x + 25.41-0.21x = 18.15,<BR>\n" );
document.write( "-0.11x = -7.26,<BR>\n" );
document.write( "x = 66 oz, amount of 10% alloy,<BR>\n" );
document.write( "121 - x = 55 oz, amount of 21% alloy.<BR>\n" );
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