document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370891>Question 370891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an office has two copiers. One makes 8 copies per minute and the other makes 10 copies per minute. If both are used at the same time to make a total of 675 copies, how many copies are made by each machine? I have the answers but I need to come up with an equation and don't know how to do that. Here are my answers: 300 copies and 375 copies. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264308 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264308\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of minutes required for both machines to make 675 copies<BR>\n" );
document.write( "Then 8x+10x=675<BR>\n" );
document.write( "18x=675<BR>\n" );
document.write( "x=37.5 min time that each machine worked in making 675 copies<BR>\n" );
document.write( "Soooo<BR>\n" );
document.write( "8*37.5=300 copies  for machine that makes 8 copies/min<BR>\n" );
document.write( "and<BR>\n" );
document.write( "10*37.5=375 copies for machine that makes 10 copies/min\r<BR>\n" );
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document.write( "ANOTHER WAY------<BR>\n" );
document.write( "Let x=# copies made by first machine (8 copies/min)<BR>\n" );
document.write( "And let y=# copies made by second machine (10 copies/min)\r<BR>\n" );
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document.write( "Soooo<BR>\n" );
document.write( "x+y=675---eq1<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x=(8/10)y-----eq2<BR>\n" );
document.write( "substitute (8/10)y for x in eq1<BR>\n" );
document.write( "(8/10)y+y=675<BR>\n" );
document.write( "(18/10)y=675<BR>\n" );
document.write( "18y=6750<BR>\n" );
document.write( "y=375-----# copies made by 2nd machine<BR>\n" );
document.write( "from eq1<BR>\n" );
document.write( "x+375=675<BR>\n" );
document.write( "x=675-375<BR>\n" );
document.write( "x=300 # copies made by 1st machine\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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