document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370860>Question 370860</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Give an example of a solution you could add to achieve the desired result. Then explain why that solution would work.: You have a 68% alcohol solution. You want to end up with a solution containing 50% alcohol. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264295 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have a 68% alcohol solution.<BR>\n" );
document.write( " You want to end up with a solution containing 50% alcohol.<BR>\n" );
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document.write( "Add pure water, let w = amt of water, start with 10 liters of 68% solution<BR>\n" );
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document.write( ".68(10) = .50(w+10)<BR>\n" );
document.write( "6.8 = .5w + 5<BR>\n" );
document.write( "6.8 - .5 = .5w<BR>\n" );
document.write( "1.8 = .5w<BR>\n" );
document.write( "multiply both sides by 2<BR>\n" );
document.write( "w = 3.6 liters of water added to 10 liters of 68% solution yields 13.6 liters of 50% solution<BR>\n" );
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document.write( "Check this, the amt of alcohol will remain the same; only the per cent changes<BR>\n" );
document.write( ".68(10) = .5(13.6)<BR>\n" );
document.write( "6.8 = 6.8 </SPAN>\n" );
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