document.write( "Question 370588: The first of two numbers minus four times a second number is at least -4. Three times the first number plus the second number is more than -3. Using x as the first number, and y as the second number, set up a system of inequalities and locate all possible solutions for x and y graphically. \n" ); document.write( "
Algebra.Com's Answer #264292 by ankor@dixie-net.com(22740)\"\" \"About 
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The first of two numbers minus four times a second number is at least -4. Three times the first number plus the second number is more than -3. Using x as the first number, and y as the second number, set up a system of inequalities and locate all possible solutions for x and y graphically.
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement, arrange for graphing:
\n" ); document.write( ":
\n" ); document.write( "\"The first of two numbers minus four times a second number is at least -4.\"
\n" ); document.write( "x - 4y => -4
\n" ); document.write( "-4y => -x - 4
\n" ); document.write( "Multiply by -1, this reverses the inequality sign
\n" ); document.write( "4y =< x + 4
\n" ); document.write( "Divide by 4
\n" ); document.write( "y =< .25x + 1; Red
\n" ); document.write( ":
\n" ); document.write( "\"Three times the first number plus the second number is more than -3.\"
\n" ); document.write( "3x + y > -3
\n" ); document.write( "y > -3x - 3; green
\n" ); document.write( ":
\n" ); document.write( "Graph these two equations
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+6%2C+-4%2C+4%2C+.25x%2B1%2C-3x-3%29+\"
\n" ); document.write( "The solution area:
\n" ); document.write( "At and below the red line
\n" ); document.write( "and
\n" ); document.write( "Above (to the right of) the green line
\n" ); document.write( ":
\n" ); document.write( "At test solution in this area: x=2, y=1
\n" ); document.write( "x - 4y => -4
\n" ); document.write( "2 - 4(1) =
\n" ); document.write( "2 - 4 = -2 (greater than -4)
\n" ); document.write( "and
\n" ); document.write( "3x + y > -3
\n" ); document.write( "3(2) + 1 =
\n" ); document.write( "6 + 1 = 7 greater than -3 \n" ); document.write( "
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