document.write( "Question 370847: I need to factor the following problem: 6x^2 - 13x + 6\r
\n" ); document.write( "\n" ); document.write( "It is not making sense to me at all. \r
\n" ); document.write( "\n" ); document.write( "6x(x-____+ 1) ??? Is this the start?
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Algebra.Com's Answer #264290 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "factor the following problem:
\n" ); document.write( "6x^2 - 13x + 6
\n" ); document.write( "factoring will result in 2 products:
\n" ); document.write( "(?x - ?)(?x - ?) Asking ourselves what 2 numbers have a product of 6?
\n" ); document.write( "Both 2*3 and 6*1 could work for this trinomial for the coefficient of x^2 and the constant.
\n" ); document.write( "Trying various combinations to complete the factoring
\n" ); document.write( "(3x - ?)(2x - ?)
\n" ); document.write( "We NEED the 'sum of the inner and outer products' to match the middle term -13x.
\n" ); document.write( "(3x - 2)(2x - 3)this arrangement works as:
\n" ); document.write( "SUM of the outer product(-9x) and the inner product(-4x) = -13x\r
\n" ); document.write( "\n" ); document.write( "checking our answer
\n" ); document.write( "(3x - 2)(2x - 3) = 3x(2x-3) -2(2x-3) = 6x^2 -9x -4x +6 = 6x^2 -13x + 6
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