document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370763>Question 370763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Gone fishing. Debbie traveled by boat 5 miles upstream to fish in her favorite spot. Because of the 4-mph current, it took her 20 minutes longer to get there than to return. How fast will her boat go in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264285 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> t = d / r ___ the upstream time is 1/3 h (20 min) longer\r<BR>\n" );
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document.write( "5 / (b - 4) = [5 / (b + 4)] + (1/3)\r<BR>\n" );
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document.write( "multiplying by 3(b-4)(b+4) ___ 15b + 60 = 15b - 60 + b^2 - 16\r<BR>\n" );
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document.write( "b^2 - 136 = 0\r<BR>\n" );
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