document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370666>Question 370666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here is my second question.\r<BR>\n" );
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document.write( "Find the slope of a line perpendicular to the line that passes through the following points.\r<BR>\n" );
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document.write( "(3,9) and (7,15) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264236 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given 2 points example. <BR>\n" );
document.write( "Find the equation of the line thru the points (2,1) and (3,5)<BR>\n" );
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document.write( "This is a 2 step process.  First find the slope of the line thru the points.<BR>\n" );
document.write( "slope, m = diffy/diffx<BR>\n" );
document.write( "m = (5-1)/(3-2)<BR>\n" );
document.write( "m = 4<BR>\n" );
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document.write( "Now use y = mx + b with either point to find b, the y-intercept.<BR>\n" );
document.write( "y = mx + b<BR>\n" );
document.write( "5 = 4*3 + b<BR>\n" );
document.write( "b = -7<BR>\n" );
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document.write( "y = mx + b<BR>\n" );
document.write( "y = 4x - 7 is the answer.<BR>\n" );
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document.write( "Another approach using determinants:<BR>\n" );
document.write( "|x y 1|<BR>\n" );
document.write( "|2 1 1| = 0<BR>\n" );
document.write( "|3 5 1|<BR>\n" );
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document.write( "x(1-5) - y(2-3) + 1(10-3) = 0<BR>\n" );
document.write( "-4x + y + 7 = 0<BR>\n" );
document.write( "y = 4x - 7<BR>\n" );
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document.write( "For further assistance, or to check your work, email me via the thank you note <BR>\n" );
document.write( " or at Moral Loophole@aol.com<BR>\n" );
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document.write( "A line and a point example.<BR>\n" );
document.write( "Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)<BR>\n" );
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document.write( "Find the slope of the line.  Do that by putting the equation in slope-intercept form, y = mx + b.  That means solve for y.<BR>\n" );
document.write( "9x+3y = 36<BR>\n" );
document.write( "3y= - 9x + 36<BR>\n" );
document.write( "y = -3x + 12<BR>\n" );
document.write( "The slope, m = -3<BR>\n" );
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document.write( "The slope of lines parallel is the same.<BR>\n" );
document.write( "The slope of lines perpendicular is the negative inverse, m = +1/3<BR>\n" );
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document.write( "Use y = mx + b and the point (1,2) to find b.<BR>\n" );
document.write( "2 = (1/3)*1 + b<BR>\n" );
document.write( "b = 5/3<BR>\n" );
document.write( "The equation is y = (1/3)x + 5/3 (slope-intercept form)<BR>\n" );
document.write( "x - 3y = -5 (standard form)<BR>\n" );
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document.write( "For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com </SPAN>\n" );
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