document.write( "Question 40982: ln(y-6)=ln(y+6)+ln4 \n" ); document.write( "
Algebra.Com's Answer #26421 by psbhowmick(878)\"\" \"About 
You can put this solution on YOUR website!
ln(y-6) = ln(y+6) + ln4
\n" ); document.write( "or ln(y-6) - ln(y+6) = ln4
\n" ); document.write( "or \"ln%28%28y-6%29%2F%28y%2B6%29%29+=+ln4\"
\n" ); document.write( "Therefore \"%28y-6%29%2F%28y%2B6%29+=+4\"
\n" ); document.write( "or [by componendo and dividendo]
\n" ); document.write( "or \"-2y%2F12+=+5%2F3\"
\n" ); document.write( "or y = -10\r
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\n" ); document.write( "\n" ); document.write( "This is impossible because then (y+6) and (y-6) become negative and logarithm of negative number is undefined. I think you have copied the problem wrongly. Instead of what you have written the question should be ln(y-6) = ln(y+6) - ln4. Then y = 10.
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