document.write( "Question 370476: $9500 is invested, part of it at 10% and part of it at 8%. For a certain year, the total yield is $878.00. How much was invested at each rate?\r
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document.write( "How much was invested at 10%?
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document.write( "How much was invested at 8%?\r
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document.write( "thank you \n" );
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Algebra.Com's Answer #264209 by robertb(5830)![]() ![]() You can put this solution on YOUR website! 0.10x + 0.08(9500 - x) = 878, \n" ); document.write( "0.10x + 760 - 0.08x = 878, \n" ); document.write( "0.02x = 118, \n" ); document.write( "x = 5900, the amount invested in the 10%, and 9500-5900 = 3600, invested in the 8%. \n" ); document.write( " |