document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370570>Question 370570</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given twelve consecutive odd integers, the ninth of which is R + 4, find the sum of the third and the twelfth of these odd integers. \r<BR>\n" );
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document.write( "(Translating Word Phrases into Mathematical Expression) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264207 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a9 = r + 4 = a1+ (9-1)2 = a1 + 16.  Hence a1 = r - 12.<BR>\n" );
document.write( "Thus a3 = r - 12 + 2*2 = r  -12+4 = r - 8, and <BR>\n" );
document.write( "a13 = r - 12 + 12*2 = r - 12 + 24 = r + 12.  The sum of the 3rd and 13th terms is then r - 8 + r + 12 = 2r + 4. </SPAN>\n" );
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