document.write( "Question 370513: The riverboat Hiawatha goes 30 km upstream and back in 4 hours. If the Hiawatha's speed in still water is 16 km'h, what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #264175 by scott8148(6628) You can put this solution on YOUR website! t = d / r ___ total time is 4 h\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "[30 / (16 - r)] + [30 / (16 + r)] = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "480 + 30r + 480 - 30r = 1024 - 4r^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r^2 - 16 = 0 \n" ); document.write( " |