document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370474>Question 370474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pure acid is to be added to a 5% acid solution to obtain 95L of 60% solution. What amount of each should be used?\r<BR>\n" );
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document.write( "How many lilter of 100% pure acid should be used to make the solution?\r<BR>\n" );
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document.write( "How many liter of the 5% solution should be in the mixture?\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264171 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 95-x * 1=95-x<BR>\n" );
document.write( "x * .05=.05x<BR>\n" );
document.write( "95 * .60=57<BR>\n" );
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document.write( "95-x+.05x=57<BR>\n" );
document.write( "-.95x=-38<BR>\n" );
document.write( "x=40 liters of the 5% solution should be in the mixture.<BR>\n" );
document.write( "95-40=55 liters of 100% acid should be used to make the solution.<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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