document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40859>Question 40859</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh>beginning algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The difference of two numbers is 34.  The second is 4 less than 3 times the first.  What are the two numbers?     The sum of two numbers is 92.  The second is 4 more that 3 times the first what are the two numbers?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26416 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let first number = x and second number = y.<BR>\n" );
document.write( "Their sum: x + y = 34 _________(1)<BR>\n" );
document.write( "3 times first number: 3x<BR>\n" );
document.write( "So the equation becomes y = 3x - 4 _________(2)<BR>\n" );
document.write( "Put the value of y from (2) in (1); then you find<BR>\n" );
document.write( "x + (3x - 4) = 34<BR>\n" );
document.write( "or 4x = 34 + 4 = 38<BR>\n" );
document.write( "or x = 38/4 = 19/2<BR>\n" );
document.write( "So from (2), y = 49/2<BR>\n" );
document.write( "Thus the numbers are 19/2 & 49/2 respectively.\r<BR>\n" );
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document.write( "Try the next one yourself exactly as the above solution.<BR>\n" );
document.write( "The equations are: x + y = 92 & y = 3x + 4.<BR>\n" );
document.write( "Answer: The numbers is 22 & 70. </SPAN>\n" );
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