document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40977>Question 40977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (3x-2)(5x to the second power +8x-2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26415 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For (3x - 2)(5x^2 + 8x - 2), we multiply every term in the first expression by every term in the second, kind of like a round-robin tournament, where everyone plays everyone else...so we get<BR>\n" );
document.write( "(3x - 2)(5x^2 + 8x - 2) =<BR>\n" );
document.write( "15x^3 + 24x^2 - 6x - 10x^2 - 16x + 4 =<BR>\n" );
document.write( "15x^3 + 14x^2 - 22x + 4 </SPAN>\n" );
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