document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370512>Question 370512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Liz commutes 30 mi. to her job each day. She finds that if she drives 10 mi/h faster it takes her 6 minutes less to get to work. Find her new speed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264146 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2 hour to work place every day<BR>\n" );
document.write( "speed = 30 mph<BR>\n" );
document.write( "...<BR>\n" );
document.write( "if she increases her speed by 10 mph her speed will be 30+10 = 40 mph.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "let distance to work place be x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "time taken with present speed - time taken with increased speed = 1/10 hours<BR>\n" );
document.write( "..<BR>\n" );
document.write( "t= d/r<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x/30 - x/(40)= 1/6<BR>\n" );
document.write( "LCD = 120<BR>\n" );
document.write( "(4x-3x)/120 = 1/6<BR>\n" );
document.write( "x/120 =1/6<BR>\n" );
document.write( "6x=120<BR>\n" );
document.write( "/6<BR>\n" );
document.write( "x= 20 miles distance to work<BR>\n" );
document.write( "..<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );