document.write( "Question 370581: The riverboat Hiawatha goes 30 km upstream and back in 4 hours. If the Hiawatha's speed in still water is 16 km/h, what is the speed of the current?\r
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document.write( "I set this problem up on a chart and had 30/16-r + 30/16+r = 4 and ended up getting r=16km/h. I am not quite sure if I set this problem up right. \n" );
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Algebra.Com's Answer #264134 by mananth(16949) You can put this solution on YOUR website! 30/(16-r)+30/(16+r)=4 \n" ); document.write( "30(16+r)+30(16-r)/(256-r^2)=4 \n" ); document.write( "480+30r+480-30r/(256-r^2)=4 \n" ); document.write( "960=4(256-r^2) \n" ); document.write( "/4 \n" ); document.write( "240=256-r^2 \n" ); document.write( "r^2=256-240 \n" ); document.write( "r^2=16 \n" ); document.write( "Take the square root \n" ); document.write( "r = 4 mph. \n" ); document.write( "I think you forgot to take the square root since r^2=16 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |