document.write( "Question 370575: Liz commutes 30 mi. to her job each day. She Finds that if she drives 10 mi/h faster it takes her 6 minutes less to get to work. Find her new speed.\r
\n" ); document.write( "\n" ); document.write( "I tried setting this problem up on a chart. For some reason when I worked the problem out I came out with really odd fractions, and I am not quite sure what I have done wrong. Any kind of help would truly mean a lot to me.
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Algebra.Com's Answer #264131 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "Let r represent her old speed
\n" ); document.write( "d = r*t
\n" ); document.write( "30 = r*t
\n" ); document.write( "30/r = t
\n" ); document.write( "\"30%2F%28r+%2B+10mph%29+=+t+-+1%2F10\"
\n" ); document.write( "\"30%2F%28r+%2B+10mph%29+=+%2830%2Fr%29+-+%281%2F10%29\"
\n" ); document.write( "Multiplying thru by 10r(r+10) so as all denominators = 1
\n" ); document.write( "300r = 300(r+10) - r(r+10)
\n" ); document.write( "300r = 300r + 3000 - r^ - 10r
\n" ); document.write( "r^2 + 10r - 3000 = 0
\n" ); document.write( "factor
\n" ); document.write( "(x + 60)(x-50) = 0
\n" ); document.write( "x + 60)= 0 x = -60 cannot use
\n" ); document.write( "(x-50) = 0 x = 50mph her old speed. Her new speed would be 60mph( 10mph faster) \n" ); document.write( "
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