document.write( "Question 370569: One pipe can fill a storage tank in five hours less time than a smaller second pipe can, and together they can fill it in six hours. How long would it take the larger pipe to fill it? \n" ); document.write( "
Algebra.Com's Answer #264122 by mananth(16946)\"\" \"About 
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let second pipe take x hours to fill
\n" ); document.write( "it will do 1/x of the job in 1 hour.
\n" ); document.write( "..
\n" ); document.write( "First pipe takes 5 hour less than second pipe.
\n" ); document.write( "x-5 hours
\n" ); document.write( "..
\n" ); document.write( "it can do 1/(x-5) of the job in 1hour.
\n" ); document.write( "... Together they do the job in 6 hours..
\n" ); document.write( "together they do 1/6 of the job in hour.
\n" ); document.write( "...
\n" ); document.write( "1/x + 1/(x-5 ) = 1/6
\n" ); document.write( "..
\n" ); document.write( "LCD = x(x-5)
\n" ); document.write( "(x-5+x)/(x(x-5))=1/6
\n" ); document.write( "(2x-5)/x(x-5) = 1/6
\n" ); document.write( "6(2x-5)=x(x-5)
\n" ); document.write( "12x-30=x^2-5x
\n" ); document.write( "x^2-5x-12x+30=0
\n" ); document.write( "x^2-17x+30=0\r
\n" ); document.write( "\n" ); document.write( "x^2-15x-2x+30=0
\n" ); document.write( "x(x-15)-2(x-15)=0
\n" ); document.write( "(x-15)(x-2)=0
\n" ); document.write( "x= 2 OR 15 hours
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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