document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370540>Question 370540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of a number and twice its multiplicative inverse (reciprocal) is 3.   Find the number.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264120 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x be the number<BR>\n" );
document.write( "reciprocal = 1/x<BR>\n" );
document.write( "2 times reciprocal = 2/x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+2/x = 3<BR>\n" );
document.write( "...<BR>\n" );
document.write( "(x^2+2)/x=3<BR>\n" );
document.write( "(x^2+2)=3x<BR>\n" );
document.write( "x^2-3x+2=0<BR>\n" );
document.write( "x^2-2x-x+2=0<BR>\n" );
document.write( "x(x-2)-1(x-2)=0<BR>\n" );
document.write( "(x-2)(x-1)=0<BR>\n" );
document.write( "x = 1 OR 2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );