document.write( "Question 370545: Hi, I'm having trouble graphing the following parabola:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+2y%5E2\"\r
\n" ); document.write( "\n" ); document.write( "It seems so simple. I have the vertex (0, 0) and I'm trying to find points and I'm getting the answer wrong. I found (32, 4) and (18, 3)...but these are apparently wrong. Please help!\r
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Algebra.Com's Answer #264115 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
having trouble graphing the following parabola:\r
\n" ); document.write( "\n" ); document.write( "x = 2y^2
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\n" ); document.write( "Solve for \"y\":\r
\n" ); document.write( "\n" ); document.write( "y^2 = x/2\r
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\n" ); document.write( "y = +/-sqrt(x/2)
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\n" ); document.write( "Plotting points:
\n" ); document.write( "Let x = 0, they y = 0
\n" ); document.write( "Let x = 8, then y = +2 and y = -2
\n" ); document.write( "Let x = 32, then y = +4 and y = -4
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\n" ); document.write( "Plot the points: (0,0), (8,2), (8,-2), (32,4), (32,-4)
\n" ); document.write( "and draw a parabola that opens to the right.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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