document.write( "Question 370459: If x, y, and z are positive integers with xy=24, xz=48, and yz=72, find x+y+z. \n" ); document.write( "
Algebra.Com's Answer #264099 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
If x, y, and z are positive integers with xy=24, xz=48, and yz=72, find x+y+z.
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document.write( "\"system%28yz=72%2Cxy=24%29\"\r\n" );
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document.write( "Divide equals by equals:\r\n" );
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document.write( "\"yz%2Fxy=72%2F24\"\r\n" );
document.write( "\"z%2Fx=3\"\r\n" );
document.write( "\"z=3x\"\r\n" );
document.write( "\"z%2F3=x\"\r\n" );
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document.write( "\"system%28xz=48%2Cxy=24%29\"\r\n" );
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document.write( "Divide equals by equals:\r\n" );
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document.write( "\"xz%2Fxy=48%2F24\"\r\n" );
document.write( "\"z%2Fy=2\"\r\n" );
document.write( "\"z=2y\"\r\n" );
document.write( "\"z%2F2=y\"\r\n" );
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document.write( "\"system%28z%2F3=x%2Cz%2F2=y%29\"\r\n" );
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document.write( "Multiply equals by equals:\r\n" );
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document.write( "\"z%5E2%2F6=xy\"\r\n" );
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document.write( "Substitute 24 for xy\r\n" );
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document.write( "\"z%5E2%2F6=24\"\r\n" );
document.write( "\"z%5E2=144\"\r\n" );
document.write( "\"z=12\"\r\n" );
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document.write( "Substitute 12 for z in\r\n" );
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document.write( "\"xz=48\"\r\n" );
document.write( "\"x%2812%29=48\"\r\n" );
document.write( "\"12x=48\"\r\n" );
document.write( "\"x=4\"\r\n" );
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document.write( "Substitute 4 for x in\r\n" );
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document.write( "\"xy=24\"\r\n" );
document.write( "\"4y=24\"\r\n" );
document.write( "\"y=6\"\r\n" );
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document.write( "x=4  y=6  z=12\r\n" );
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document.write( "Therefore x+y+z = 4+6+12 = 22\r\n" );
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document.write( "Edwin
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