document.write( "Question 370510: Solve algebraically giving answers in terms of π:\r
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document.write( "2sinx=1, 0 ≤ x ≤ 6π\r
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document.write( "I don't understand the steps on how to solve it. Should I divide 2 with the radian for 1? \n" );
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Algebra.Com's Answer #264089 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve algebraically giving answers in terms of π: \n" ); document.write( "2sinx=1, 0 ≤ x ≤ 6π \n" ); document.write( "---------- \n" ); document.write( "sin(x) = 1/2, \n" ); document.write( "--- \n" ); document.write( "Since x is limited to 0<= x <= 6*pi \n" ); document.write( "--- \n" ); document.write( "x = (pi/6)+ 2n(pi) where n = 0,1,2 \n" ); document.write( "or \n" ); document.write( "x = (5/6)pi + 2n(pi) where n = 0,1,2 \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |