document.write( "Question 370510: Solve algebraically giving answers in terms of π:\r
\n" ); document.write( "\n" ); document.write( "2sinx=1, 0 ≤ x ≤ 6π\r
\n" ); document.write( "\n" ); document.write( "I don't understand the steps on how to solve it. Should I divide 2 with the radian for 1?
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Algebra.Com's Answer #264089 by stanbon(75887)\"\" \"About 
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Solve algebraically giving answers in terms of π:
\n" ); document.write( "2sinx=1, 0 ≤ x ≤ 6π
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\n" ); document.write( "sin(x) = 1/2,
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\n" ); document.write( "Since x is limited to 0<= x <= 6*pi
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\n" ); document.write( "x = (pi/6)+ 2n(pi) where n = 0,1,2
\n" ); document.write( "or
\n" ); document.write( "x = (5/6)pi + 2n(pi) where n = 0,1,2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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