document.write( "Question 370490: find two consecutive positive intergers such that the square of the larger integer added to seven times the smaller integer is equal to 253? \n" ); document.write( "
Algebra.Com's Answer #264076 by checkley77(12844)\"\" \"About 
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Let x & (x+1) be the 2 integers.
\n" ); document.write( "(x+1)^2+7x=253
\n" ); document.write( "x^2+2x+1+7x=253
\n" ); document.write( "x^2+9x+1-253=0
\n" ); document.write( "x^2+9x-252=0
\n" ); document.write( "(x-12)(x+21)=0
\n" ); document.write( "x-12=0
\n" ); document.write( "x=12 ANS FOR THE SMALLER INTEGER.
\n" ); document.write( "12+1=13 ANS. FOR THE LARGER INTEGER.
\n" ); document.write( "Proof:
\n" ); document.write( "13^2+7*12=253
\n" ); document.write( "169+84=253
\n" ); document.write( "253=253
\n" ); document.write( "
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