document.write( "Question 39858: My friend and I are trying to see who has the right answer to some problems. Could you please explain to us how to solve them the right way.\r
\n" ); document.write( "\n" ); document.write( "a. The monthly revenue achieved by selling x boxes of candy is calculated to be $ x(5-0.05x). The wholesale cost of each box of candy is $1.50.
\n" ); document.write( "How many boxes must be sold each month to maximize profit?
\n" ); document.write( "What is the maximum profit?
\n" ); document.write( "(Revenue=Cost+Profit)\r
\n" ); document.write( "\n" ); document.write( "b. Bob has 3000ft of fencing available to enclose a rectangular field.
\n" ); document.write( "1. Express the area A of rectangle as a function of x where x is the length of rectangle.
\n" ); document.write( "2. For what value of x is the area largest?
\n" ); document.write( "3.What is the maximum area?\r
\n" ); document.write( "\n" ); document.write( "Thank you so much! Now we will see who is right:)
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Algebra.Com's Answer #26407 by psbhowmick(878)\"\" \"About 
You can put this solution on YOUR website!
1. The total profit by selling 'x' boxes of candies is
\n" ); document.write( "P = $(x(5-0.05x) - 1.5x) = $\"%283.5x+-+0.05x%5E2%29\"
\n" ); document.write( "For maximizing 'P', \"dP%2Fdx+=+0\" and \"d%5E2P%2Fdx%5E2+%3C+0\"
\n" ); document.write( "Now, \"dp%2Fdx+=+0+=+3.5+-+2%2A0.05%2Ax+=+3.5+-+0.1x\"
\n" ); document.write( "or x = 35
\n" ); document.write( "and \"d%5E2p%2Fdx%5E2+=++-+2%2A0.05+=+-0.1\"
\n" ); document.write( "Thus P is maximum for x = 35 and corresponding P = $\"%283.5%2A35+-+0.05%2A35%5E2%29\" = $61.25.
\n" ); document.write( "So for maximum profit, 35 boxes are to be sold and the maximum profit is $61.25.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2. Perimeter = 3000 ft.
\n" ); document.write( "Let length = L ft, width = W ft of the rectangular field.
\n" ); document.write( "Then, 2(L + W) = 3000 or L + W = 1500 _________(1)
\n" ); document.write( "Given: L = x, then from (1) W = 1500 - x.
\n" ); document.write( "Hence, area A = \"L%2AW+=+x%2A%281500-x%29\" sq ft
\n" ); document.write( "To find maximum area, maximize A w.r.t x as done in the problem above.
\n" ); document.write( "Then you get, x = 750 for maximum A and this maximum value of A is \"750%2A750\" = 562500
\n" ); document.write( "Hence area of the rectangular field is maximum when its each side is 750 ft i.e. the field is a square with side 750 ft and this maximum area enclosed is 562500 sq ft.\r
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\n" ); document.write( "\n" ); document.write( "[V.V.I.: From this problem we come to the conclusion that of all rectangles with same perimeter, the square has the largest area.]
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