document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215032>Question 215032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm actually in pre-calc...i just couldn't find a category for it.\r<BR>\n" );
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document.write( "here's my problem!\r<BR>\n" );
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document.write( "A ship travels 58 km on a bearing of 20 degrees, and then travels on a bearing of 110 degrees for 133 km. Find the distance from the starting point to the end of the trip, to the nearest kilometer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264014 by </B><A HREF=/tutors/aboutme.mpl?userid=rfadrogane><B>rfadrogane(214)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfadrogane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rfadrogane><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264014\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since it forms a right triangle after you simplify, therefore:<BR>\n" );
document.write( "d = sq. root (58^2 + 133^2)<BR>\n" );
document.write( "d = 145-km </SPAN>\n" );
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