document.write( "Question 370382: find two consecutive odd integers such that five times the first integer is 25 less than twice the greater integer \n" ); document.write( "
Algebra.Com's Answer #264008 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Let x represent the smaller of the two consecutive odd integers.
\n" ); document.write( "the other then would be (x+2)
\n" ); document.write( "Write as we Read
\n" ); document.write( "5x = 2(x+2) - 25
\n" ); document.write( "solving for x
\n" ); document.write( "5x = 2x + 4 - 25
\n" ); document.write( "3x = -21
\n" ); document.write( "x = -7, the smaller consecutive odd integers. The larger is -5 (-7+2)
\n" ); document.write( "Checking our answer
\n" ); document.write( "5*-7 = 2*-5 - 25 = 35 \n" ); document.write( "
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