document.write( "Question 370377: x+2x^1/2-15=0\r
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Algebra.Com's Answer #264000 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "x+2x^1/2-15=0
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document.write( "solve by first writing it as a quadratic equation
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document.write( "2x^1/2= 15-x
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document.write( "squaring both sides of the equation
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document.write( "4x = (15-x)(15-x)
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document.write( "4x = 225 - 30x + x^2
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document.write( "x^2 -34x + 225 = 0
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document.write( "factoring
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document.write( "(x-25)(x-9)= 0
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document.write( "(x-25)=0
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document.write( "x = 25
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document.write( "(x-9)= 0
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document.write( "x = 9 \n" );
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