document.write( "Question 370353: 1) A fish can swim at 14m/s with the current and at 6m/s against it. Find the speed of the current and the speed of the fish in still water.\r
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document.write( "2) If the numerator and denominator of a fraction are both decreased by one the fraction becomes 2/3. If the numerator and denominator are both increased by one the fraction becomes 3/4. Find the original fraction. \n" );
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Algebra.Com's Answer #263961 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let speed of fish in still water be x \n" ); document.write( "let speed of current be y m/s \n" ); document.write( ".. \n" ); document.write( "x+y =14 \n" ); document.write( "x-y =6 \n" ); document.write( "add the equations \n" ); document.write( "2x=20 \n" ); document.write( "/2 \n" ); document.write( "x= 10 m/s \n" ); document.write( "y = 4m/s \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "... \n" ); document.write( "let the numerator be x \n" ); document.write( "denominator be y \n" ); document.write( "... \n" ); document.write( "(x-1)/(y-1) =2/3 \n" ); document.write( "3(x-1)=2(y-1) \n" ); document.write( "3x-3=2y-2 \n" ); document.write( "3x-2y =1.................1 \n" ); document.write( "... \n" ); document.write( "(x+1)/(y+1)=3/4 \n" ); document.write( "4(x+1)=3(y+1) \n" ); document.write( "4x+4 = 3y+3 \n" ); document.write( "4x-3y=-1................2 \n" ); document.write( "multiply equation 1 by -3 & equation (2) by 2 \n" ); document.write( "-9x+6y=-3 \n" ); document.write( "8x-6y=-2 \n" ); document.write( "add i \n" ); document.write( "-x=-5 \n" ); document.write( "x=5 \n" ); document.write( ".. \n" ); document.write( "plug value of x in (1) \n" ); document.write( "3*(5)-2y = 1 \n" ); document.write( "-2y= -14 \n" ); document.write( "/-2 \n" ); document.write( "y=7 \n" ); document.write( ".. \n" ); document.write( "Fraction = 5/7 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |