document.write( "Question 370353: 1) A fish can swim at 14m/s with the current and at 6m/s against it. Find the speed of the current and the speed of the fish in still water.\r
\n" ); document.write( "\n" ); document.write( "2) If the numerator and denominator of a fraction are both decreased by one the fraction becomes 2/3. If the numerator and denominator are both increased by one the fraction becomes 3/4. Find the original fraction.
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Algebra.Com's Answer #263961 by mananth(16946)\"\" \"About 
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let speed of fish in still water be x
\n" ); document.write( "let speed of current be y m/s
\n" ); document.write( "..
\n" ); document.write( "x+y =14
\n" ); document.write( "x-y =6
\n" ); document.write( "add the equations
\n" ); document.write( "2x=20
\n" ); document.write( "/2
\n" ); document.write( "x= 10 m/s
\n" ); document.write( "y = 4m/s
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "...
\n" ); document.write( "let the numerator be x
\n" ); document.write( "denominator be y
\n" ); document.write( "...
\n" ); document.write( "(x-1)/(y-1) =2/3
\n" ); document.write( "3(x-1)=2(y-1)
\n" ); document.write( "3x-3=2y-2
\n" ); document.write( "3x-2y =1.................1
\n" ); document.write( "...
\n" ); document.write( "(x+1)/(y+1)=3/4
\n" ); document.write( "4(x+1)=3(y+1)
\n" ); document.write( "4x+4 = 3y+3
\n" ); document.write( "4x-3y=-1................2
\n" ); document.write( "multiply equation 1 by -3 & equation (2) by 2
\n" ); document.write( "-9x+6y=-3
\n" ); document.write( "8x-6y=-2
\n" ); document.write( "add i
\n" ); document.write( "-x=-5
\n" ); document.write( "x=5
\n" ); document.write( "..
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "3*(5)-2y = 1
\n" ); document.write( "-2y= -14
\n" ); document.write( "/-2
\n" ); document.write( "y=7
\n" ); document.write( "..
\n" ); document.write( "Fraction = 5/7
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca\r
\n" ); document.write( "\n" ); document.write( "
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