document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370296>Question 370296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangle is 238 and the length is 75 more than the width, what is the length and the width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #263948 by </B><A HREF=/tutors/aboutme.mpl?userid=lefty4ever26><B>lefty4ever26(59)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lefty4ever26><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lefty4ever26><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=263948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=75+W<BR>\n" );
document.write( "Perimeter means add up all the sides.  L+L+W+W.  Replace the L's with (75+W)\r<BR>\n" );
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document.write( "(75+W)+(75+W)+W+W=238<BR>\n" );
document.write( "150+4W=238<BR>\n" );
document.write( "4W=88<BR>\n" );
document.write( "W=22  SO if the Width is 22 then the Length is 22+75=97. </SPAN>\n" );
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