document.write( "Question 370283: the perimeter of a rectangle is 116m. the length is 7 m more than twice the width. find the dimensions \n" ); document.write( "
Algebra.Com's Answer #263924 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let width be x \n" ); document.write( "length = 2x+7 \n" ); document.write( "... \n" ); document.write( "Perimeter = 2L+2W \n" ); document.write( "2x+2(2x+7)=116 \n" ); document.write( ".. \n" ); document.write( "2x+4x+14=116 \n" ); document.write( "6x+14=116 \n" ); document.write( "-14 -14 \n" ); document.write( "6x=116-14 \n" ); document.write( "6x=102 \n" ); document.write( "/6 \n" ); document.write( "x= 102/6 \n" ); document.write( "x= 17 m the width. \n" ); document.write( "Length = 2*17+7 = 41 m \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |