document.write( "Question 370283: the perimeter of a rectangle is 116m. the length is 7 m more than twice the width. find the dimensions \n" ); document.write( "
Algebra.Com's Answer #263924 by mananth(16946)\"\" \"About 
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let width be x
\n" ); document.write( "length = 2x+7
\n" ); document.write( "...
\n" ); document.write( "Perimeter = 2L+2W
\n" ); document.write( "2x+2(2x+7)=116
\n" ); document.write( "..
\n" ); document.write( "2x+4x+14=116
\n" ); document.write( "6x+14=116
\n" ); document.write( "-14 -14
\n" ); document.write( "6x=116-14
\n" ); document.write( "6x=102
\n" ); document.write( "/6
\n" ); document.write( "x= 102/6
\n" ); document.write( "x= 17 m the width.
\n" ); document.write( "Length = 2*17+7 = 41 m
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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