document.write( "Question 370121: Why do we divide by 2 when solving problems involving gravity, 32 feet per second per second? \n" ); document.write( "

Algebra.Com's Answer #263918 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"a=dv%2Fdt=-g\"$
\n" ); document.write( " $\"v=dx%2Fdt=-gt%2Bv0\"$
\n" ); document.write( " $\"x=-%281%2F2%29gt%5E2%2Bv0%2At%2Bx0\"$
\n" ); document.write( "Since acceleration is the derivative of velocity, when you integrate you get a term gravity linear in $\"t\"$ .
\n" ); document.write( "When you integrate velocity to get position, that linear term becomes a quadratuc term in $\"t\"$ the 1/2 is brought out during integration.
\n" ); document.write( "Hopefully that made sense to you.
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